Talk:Diexponae

this is... not a new computational class. just cuz it uses the quadratic formula doesn't mean its a new computational class Yayimhere (talk) 12:35, 27 August 2024 (UTC)

Wouldn't there be more computations you can solve on a finite memory if the memory grows quadratically rather than linearly on the size of the input? Also I never really knew what this would be considered as, and I threw this together in an hour. If it's not a new computational class, that's fine; I don't really care much about this language anymore. BoundedBeans (talk) 17:13, 27 August 2024 (UTC)