FizzBuzz
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A FizzBuzz program is essentially a counting program. It prints all integers in a certain range, generally 1 to 100, one-by-one. However, multiples of 3 are replaced with "Fizz", and multiples of 5 are replaced with "Buzz". Multiples of 15 (e.g., multiples of lcm(3, 5)) are replaced with "FizzBuzz".
In other words, the program outputs:
1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 ...
There also exist variants where the multipliers are different from 3 and 5, eg. 4 and 7 are common.
History
FizzBuzz originated as a non-computer educational game where a group of children sit in a circle and take turns counting, replacing numbers with "fizz" and "buzz" when required. When a child makes a number of mistakes or fails to go as fast as possible, they are eliminated from the game. FizzBuzz gained wider popularity as a programming question in 2007 following several popular blog posts which discussed it as an example of a problem that most applicants for professional programming jobs cannot complete.[1][2][3]
Domain-specific languages
The following languages are designed specifically to implement FizzBuzz and variants:
See also BuzzFizz, which was designed as a general-purpose esolang made out of the primitives needed to implement FizzBuzz.
Examples
brainfuck
>>>>>>>>>>>>>>>[-]+>[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++>[-]+<<<[-]<[-]>>>[<<<+>>>-]+<[<<->+>-]<[>+<-]<[>>>-<<<[-]]>[-]>>[>-<<<+>>-]<<[>>+<<-]>>>[>[-]<<<[>>>+<<<<<<<<<<<<<<<<<<+>>>>>>>>>>>>>>>-]<<<<<<<<<<<<<<<[>>>>>>>>>>>>>>>+<<<<<<<<<<<<<<<-]>>>>>>>>>>>>>>>>>>[<<<<<<<<<<<<<<<<<+>>>>>>>>>>>>>>>>>-]<<<<<<<<<<<<<<<+++<<[>+>->+<[>]>[<+>-]<<[<]>-]>[-]>[-]>[>>>>>>>>>>>>>>+<<<<<<<<<<<<<<-]>>>>>>>>>>>>>>>[-]<<<<[>>>>+<<<<<<<<<<<<<<<<<<<+>>>>>>>>>>>>>>>-]<<<<<<<<<<<<<<<[>>>>>>>>>>>>>>>+<<<<<<<<<<<<<<<-]>>>>>>>>>>>>>>>>>>>[<<<<<<<<<<<<<<<<<<+>>>>>>>>>>>>>>>>>>-]<<<<<<<<<<<<<<<<+++++<<[>+>->+<[>]>[<+>-]<<[<]>-]>[-]>[-]>[>>>>>>>>>>>>>>>+<<<<<<<<<<<<<<<-]>>>>>>>>>>>>>>>>[-]>[-]<<<[>>+>+<<<-]>>[<<+>>-]+>[>>[-]>[-]<<<<<[>>>>+>+<<<<<-]>>>>[<<<<+>>>>-]+>[<<<<<<<<<[<<<<<<<<<<<<<<<+>>>>>>>>>>>>>>+>-]<<<<<<<<<<<<<<[-]>[-]+>[-]+<[>[-<-<<[->+>+<<]>[-<+>]>>]++++++++++>[-]+>[-]>[-]>[-]<<<<<[->-[>+>>]>[[-<+>]+>+>>]<<<<<]>>-[-<<+>>]<[-]++++++++[-<++++++>]>>[-<<+>>]<<]<[.[-]<]<[-]>>>>>>>>>>>>>>[>+<-]>>>>>>>>>->[-]]<[<<<<<<<<<++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]>>>>>>>>>-]<<<->[-]]<[>>>>>>[-]>[-]<<<<<<<<[>>>>>>>+>+<<<<<<<<-]>>>>>>>[<<<<<<<+>>>>>>>-]+>[<<<<<<<<<<<<<++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]>>>>>>>>>>>>->[-]]<[<<<<<<<<<<<<++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.[-]>>>>>>>>>>>>-]<<<<<<-]<<<<<<<[-]++++++++++.[-]>>+>[-]+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++>[-]+<<<[-]<[-]>>>[<<<+>>>-]+<[<<->+>-]<[>+<-]<[>>>-<<<[-]]>[-]>>[>-<<<+>>-]<<[>>+<<-]>>>]
Compiled using BFFuck, source code here.
Befunge
>1+:3%!#v_>:5%!#v_v
^,*52.:_ `@#\"d" :<
v"Fizz"< >v
>,,,,:5% |
v"Buzz"<<
>,,,,v
^ ,*52< <
More Compact Version:
>1+:3%!#v_>:5%!#v_v
^,*52.:_ `@#\"d" :<
v"Fizz"< >v
>,,,,:5% |
v,,,,"Buzz"<<
^,*52< <
BunnyBell
include lib/Math/Ops.bbe
func @main char @c int @i 0 label @loop beq ((:mod &i 15) 0)) FizzBuzz beq ((:mod &i 5) 0)) Buzz beq ((:mod &i 3) 0)) Fizz goto nonCase
label @Fizz out "Fizz\n" goto loopEnd
label @Buzz out "Buzz\n" goto loopEnd
label @FizzBuzz out "FizzBuzz\n" goto loopEnd
label @nonCase out &i out "\n"
label @loopEnd give &i 1 bleq &i 100 loop return
BuzzFizz
if max\$a: # do nothing else: # do nothing $a++ if 3\$a: print "Fizz" if 5\$a: print "Buzz" else: print $a print "\n" if max\$a: # do nothing else: loop
C
#include <stdio.h>
int main(void)
{
int i;
for(i=1; i<=100; i++)
{
if((i%15)== 0)//improved from "(i%3)&&(i%5)"
printf("FizzBuzz\n");
else if((i%3)==0)
printf("Fizz\n");
else if((i%5)==0)
printf("Buzz\n");
else
printf("%d\n",i);
}
return 0;
}
A more cleaned up version:
#include <stdio.h>
int main () {
char *fizz;
char *buzz;
for (int i = 1; i <= 100; i++) {
fizz = (i % 3 == 0) ? "Fizz" : ""; // Fizz on 3's
buzz = (i % 5 == 0) ? "Buzz" : ""; // Buzz on 5's
if (i % 3 == 0 || i % 5 == 0) {
printf("%s%s\n", fizz, buzz);
} else {
printf("%d\n", i)
}
}
return 0;
}
Chinese
定义 甲 为 整数， 赋值为 1
重复执行直到 （甲 < 100） 不满足
{
如果 (甲 取模 3 等于 0) 则：
{
打印 "Fizz"
}
如果 (甲 取模 5 等于 0) 则：
{
打印 "Buzz"
}
如果 (甲 取模 3 不等于 0 且 甲 取模 5 不等于 0) 则：
{
打印 甲
}
打印 "\n"
}
DIVSPL
1..100 Fizz=3 Buzz=5
Empty
Sl+∅1^∅TlTfTuTiM∅5^∅4+∅5^∅4+∅5^∅;∅f∅7;∅8^∅iSf#Fizz:∅7;∅8^∅nSiM∅5^∅4+∅5^∅4+∅5^∅4+∅5^∅4+∅5^∅;∅b∅7;∅8^∅uTbSb"B+uzz:∅7;∅8^∅nSu:#TnSn ∅9^∅9•∅l
Fizzbuzz
Fzzbzz
<1/3=fizz,5=buzz/100>
GotoScript
# Variables 1 max := 100 2 n := 0 3 to_print := "" # Conditionals 4 GOTO 8 IF n % 15 = 0 5 GOTO 9 IF n % 3 = 0 6 GOTO 10 IF n % 5 = 0 # Print options 7 to_print := n 8 to_print := 'FizzBuzz' 9 to_print := 'Fizz' 10 to_print := 'Buzz' # Output 11 GOTO 12 WHEN to_print != "" 12 PRINT to_print # Continue loop 13 n += 1 14 GOTO 3 # End loop 15 GOTO WHEN n > max
Lazy K
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Shorter, but slower version:
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It's probably not correct to speak of Lazy K program being slower or faster than the other one due to the nature of Lazy K and combinator calculus in general. Both functions are equivalent (in some way) because both ignore their arguments and return the same constant (infinite Church list of Church numerals that represents the only valid output of FizzBuzz program). Probably, the closest analogy is two infinite series that converge to the same value.
Mathematics
(i.e. "Fizz")
(i.e. "Buzz")
gives
[1, 2, -4122, 4, -8022, -4122, 7, 8, -4122, -8022, 11, -4122, 13, 14, -41228022, 16, ...]
Python equivalent:
from math import floor, ceil phi = -4122 beta = -8022 fb = lambda x: x * ceil(x/3 - x//3) * ceil(x/5 - x//5) + beta * (1 + floor(x//5 - x/5)) + phi * (1 + floor(x//3 - x/3)) * (1 + (1 + floor(x//5 - x/5)) * 9999) [fb(i) for i in range(1, 31)]
MoreMathRPN
repeat 50 >>> 0 1 >> 1 3 % step 4 * jmp ]0 * outputS "Fizz" jmp 2 del 0 >> 1 5 % step 4 * jmp ]0 * outputS "Buzz" jmp 2 del 0 2 * jmp ]0 jmp 3 -> 1 outputV jmp 2 del 0 del 0 outputS ", " next
Muriel
S:"\"S:\\\"\"+|S+\"\\\";\\ni:\"+$(i+(f=3))+\";a:\"+$((i*(f=0))+((a-(3*(a>2)))*(f=1))+(a*((f=2)+(f=3))))+\";b:\"+$((i*(f=0))+((b-(5*(b>4)))*(f=2))+(b*((f=1)+(f=3))))+\";f:\"+$((f=0)+((2-(a>2))*(f=1))+((3-(b>4))*(f=2)))+\";\\n.(%\\\"Fizz\\\",0,4*(f=3)*(a=0))+(%\\\"Buzz\\\",0,4*(f=3)*(b=0))+(%$i,0,#$i*(f=3)*(a=0=0)*(b=0=0))+(%\\\"\\\\n\\\",0,(f=3));\\nT:\"+S+\";\\n@%T,0,(&T*(101>i))\""; i:1;a:1;b:1;f:0; .(%"Fizz",0,4*(f=3)*(a=0))+(%"Buzz",0,4*(f=3)*(b=0))+(%$i,0,#$i*(f=3)*(a=0=0)*(b=0=0))+(%"\n",0,(f=3)); T:"S:\""+|S+"\";\ni:"+$(i+(f=3))+";a:"+$((i*(f=0))+((a-(3*(a>2)))*(f=1))+(a*((f=2)+(f=3))))+";b:"+$((i*(f=0))+((b-(5*(b>4)))*(f=2))+(b*((f=1)+(f=3))))+";f:"+$((f=0)+((2-(a>2))*(f=1))+((3-(b>4))*(f=2)))+";\n.(%\"Fizz\",0,4*(f=3)*(a=0))+(%\"Buzz\",0,4*(f=3)*(b=0))+(%$i,0,#$i*(f=3)*(a=0=0)*(b=0=0))+(%\"\\n\",0,(f=3));\nT:"+S+";\n@%T,0,(&T*(101>i))"; @%T,0,(&T*(101>i))
Python 3
for i in range(1,101):
if i%3==0:
print("Fizz",end="")
if i%5==0:
print("Buzz",end="")
if i%3 and i%5:
print(i,end="")
print()
Satarcrimp
KW)(C$ki9kuhm4otjy[90ju{)($%K)W($LV:}
IMW$(C}MTW{#IJT
W$ FIZZBUZZ![0u,IWL_
VL
_L{
Li0
[MSI)
NTSIRP<SROPHI8op94769y8oUW)_KV}_$LVW)4]
Standard modern vernacular
定义整型变量 A ，然后初始化为 1 。
重复执行以下代码块直到 A <= 100 这个条件不满足为止：
如果 A%3=0 则：
输出"Fizz"。
如果 A%5=0 则：
输出"Buzz"。
如果 A%3!=0 且 A%5!=0 则：
输出 A 。
输出一个换行符。
将 A 加上 1。
Stringle
i "!" f "!" b "!" z 1 z p "" #f 3 p "Fizz" #f 3 f "" #b 5 p p "Buzz" #b 5 b "" #p !0 $ p #p 0 $ #i #i +100 z 0 i i "!" f f "!" b b "!" z
TeX
\newcount\-\let~\advance\day0\loop~\-1~\day1~\mit\ifnum\-=3\-0Fizz\fi\ifnum\fam=5Buzz\rm\fi\ifvmode\the\day\fi\endgraf\ifnum\day<`d\repeat\bye
Thue
FizBuzz in Thue by Amb ::= >t|::=t> >f|::=f> >|::=|> >tf::=t||>fF >f?::=f||||>?B F|::=|F F?::=?F >?n::=?n>pp[sp] >?Fn::=?n>[fi[sp]zz] >?Bn::=?n>[bu[sp]zz] >?BFn::=?n>[fizz[sp]buzz] [sp]::=~ [fizz]::=~Fizz [buzz]::=~Buzz [fizzbuzz]::=~FizzBuzz pp0::=0p[0]p pp1::=1p[1]p pp2::=2p[2]p pp3::=3p[3]p pp4::=4p[4]p pp5::=5p[5]p pp6::=6p[6]p pp7::=7p[7]p pp8::=8p[8]p pp9::=9p[9]p [0]::=~0 [1]::=~1 [2]::=~2 [3]::=~3 [4]::=~4 [5]::=~5 [6]::=~6 [7]::=~7 [8]::=~8 [9]::=~9 pp$::=$ >0::=0> >1::=1> >2::=2> >3::=3> >4::=4> >5::=5> >6::=6> >7::=7> >8::=8> >9::=9> >$::=+$ 0+::=-1 1+::=-2 2+::=-3 3+::=-4 4+::=-5 5+::=-6 6+::=-7 7+::=-8 8+::=-9 9+::=+0 0-::=-0 1-::=-1 2-::=-2 3-::=-3 4-::=-4 5-::=-5 6-::=-6 7-::=-7 8-::=-8 9-::=-9 n+::=<n1 n-::=<n ?<::=<? f<::=<f t<::=<t |<::=<| ^<::=^> ::= ^>t||f||||?n1$
another by User: Jan jelo
o0::=~0 o1::=~1 o2::=~2 o3::=~3 o4::=~4 o5::=~5 o6::=~6 o7::=~7 o8::=~8 o9::=~9 0[<0]::=0[3>] 1[<0]::=[<1]1 2[<0]::=2[3>] 3[<0]::=3[3>] 4[<0]::=4[3>] 5[<0]::=5[3>] 6[<0]::=6[3>] 7[<0]::=7[3>] 8[<0]::=8[3>] 9[<0]::=9[3>] |[<0]::=|[3>] 0[<1]::=[<2]0 1[<1]::=1[3>] 2[<1]::=2[3>] 3[<1]::=3[3>] 4[<1]::=4[3>] 5[<1]::=5[3>] 6[<1]::=6[3>] 7[<1]::=7[3>] 8[<1]::=8[3>] 9[<1]::=9[3>] |[<1]::=|[3>] 0[<2]::=0[3>] 1[<2]::=[Halt]1 2[<2]::=2[3>] 3[<2]::=3[3>] 4[<2]::=4[3>] 5[<2]::=5[3>] 6[<2]::=6[3>] 7[<2]::=7[3>] 8[<2]::=8[3>] 9[<2]::=9[3>] |[<0]::=|[3>] [3>]0::=0[3>] [3>]1::=1[3>] [3>]2::=2[3>] [3>]3::=3[3>] [3>]4::=4[3>] [3>]5::=5[3>] [3>]6::=6[3>] [3>]7::=7[3>] [3>]8::=8[3>] [3>]9::=9[3>] [3>]|::=[<4]| 0[<4]::=[<4]0 1[<4]::=[<4]1[*>] 2[<4]::=[<4]2[*>][*>] 3[<4]::=[<4]3[*>][*>][*>] 4[<4]::=[<4]4[*>][*>][*>][*>] 5[<4]::=[<4]5[*>][*>][*>][*>][*>] 6[<4]::=[<4]6[*>][*>][*>][*>][*>][*>] 7[<4]::=[<4]7[*>][*>][*>][*>][*>][*>][*>] 8[<4]::=[<4]8[*>][*>][*>][*>][*>][*>][*>][*>] 9[<4]::=[<4]9[*>][*>][*>][*>][*>][*>][*>][*>][*>] |[<4]::=|[5>] [*>]0::=0[*>] [*>]1::=1[*>] [*>]2::=2[*>] [*>]3::=3[*>] [*>]4::=4[*>] [*>]5::=5[*>] [*>]6::=6[*>] [*>]7::=7[*>] [*>]8::=8[*>] [*>]9::=9[*>] [*>]|::=|* Fizz::=~Fizz [5>]0::=0[5>] [5>]1::=1[5>] [5>]2::=2[5>] [5>]3::=3[5>] [5>]4::=4[5>] [5>]5::=5[5>] [5>]6::=6[5>] [5>]7::=7[5>] [5>]8::=8[5>] [5>]9::=9[5>] [5>]|***::=[5>]| [5>]||::=Fizz[<6]|| [5>]|*|::=[<7]|| [5>]|**|::=[<7]|| Buzz::=~Buzz 0[<6]::=0Buzz[<8] 1[<6]::=1[<8] 2[<6]::=2[<8] 3[<6]::=3[<8] 4[<6]::=4[<8] 5[<6]::=5Buzz[<8] 6[<6]::=6[<8] 7[<6]::=7[<8] 8[<6]::=8[<8] 9[<6]::=9[<8] 0[<7]::=0Buzz[<8] 1[<7]::=1[<9] 2[<7]::=2[<9] 3[<7]::=3[<9] 4[<7]::=4[<9] 5[<7]::=5Buzz[<8] 6[<7]::=6[<9] 7[<7]::=7[<9] 8[<7]::=8[<9] 9[<7]::=9[<9] 0[<8]::=1[11>] 1[<8]::=2[11>] 2[<8]::=3[11>] 3[<8]::=4[11>] 4[<8]::=5[11>] 5[<8]::=6[11>] 6[<8]::=7[11>] 7[<8]::=8[11>] 8[<8]::=9[11>] 9[<8]::=[<8]0 |[<8]::=|0[<8] 0[<9]::=[<9]0 1[<9]::=[<9]1 2[<9]::=[<9]2 3[<9]::=[<9]3 4[<9]::=[<9]4 5[<9]::=[<9]5 6[<9]::=[<9]6 7[<9]::=[<9]7 8[<9]::=[<9]8 9[<9]::=[<9]9 |[<9]::=|[10>] [10>]0::=0[10>]o0 [10>]1::=1[10>]o1 [10>]2::=2[10>]o2 [10>]3::=3[10>]o3 [10>]4::=4[10>]o4 [10>]5::=5[10>]o5 [10>]6::=6[10>]o6 [10>]7::=7[10>]o7 [10>]8::=8[10>]o8 [10>]9::=9[10>]o9 [10>]|::=[<8]| Sep::=~; [11>]0::=0[11>] [11>]1::=1[11>] [11>]2::=2[11>] [11>]3::=3[11>] [11>]4::=4[11>] [11>]5::=5[11>] [11>]6::=6[11>] [11>]7::=7[11>] [11>]8::=8[11>] [11>]9::=9[11>] [11>]|::=Sep[<0]| ::= |1[<0]||
Uiua
⍢(+1&p""&pf⨬("FizzBuzz"|"Fizz"|"Buzz"|∘)+>0◿5,×2>0◿3..|<101)1
A shorter one:
∵(&p⨬(∘|"Buzz"|"Fizz"|"FizzBuzz"))+=0◿5,×2=0◿3.+1⇡100
Vyxal
Ĥƛ3∻ı½¬*n5∻ı½∧*+n⟇
wenyan
It may output as Chinese. Fizz is replaced by 黃河流水鳴濺濺。, and Buzz is replaced by 燕山胡騎鳴啾啾。.
有數一。名之曰「戊」。恆為是。 除「戊」以三。所餘幾何。變其。名之曰「三餘」。 除「戊」以五。所餘幾何。變其。名之曰「五餘」。 夫「三餘」「五餘」中有陽乎。變其。名之曰「寂」。 若「寂」者。吾有一言。曰「戊」。書之。 若非。 吾有一言。名之曰「聲」。 若「三餘」者。加「聲」以「「黃河流水鳴濺濺。」」。昔之「聲」者。今其是矣。云云。 若「五餘」者。加「聲」以「「燕山胡騎鳴啾啾。」」。昔之「聲」者。今其是矣。云云。 吾有一言。曰「聲」。書之。 云云。 若「戊」等於一百者乃止也。 加一以「戊」。昔之「戊」者。今其是矣。 云云。
And Correct Version(If you're in Wenyan Online IDE, Please uncheck [Print Hanzi]):
有數一。名之曰「戊」。恆為是。 除「戊」以三。所餘幾何。變其。名之曰「三餘」。 除「戊」以五。所餘幾何。變其。名之曰「五餘」。 夫「三餘」「五餘」中有陽乎。變其。名之曰「寂」。 若「寂」者。吾有一言。曰「戊」。書之。 若非。 吾有一言。名之曰「聲」。 若「三餘」者。加「聲」以「「Fizz」」。昔之「聲」者。今其是矣。云云。 若「五餘」者。加「聲」以「「Buzz」」。昔之「聲」者。今其是矣。云云。 吾有一言。曰「聲」。書之。 云云。 若「戊」等於一百者乃止也。 加一以「戊」。昔之「戊」者。今其是矣。 云云。
WhatLang
¿1:101-{::3%~2*\5%~+[(:)((Buzz))((Fizz))((FizzBuzz))]\,\_@._10chr@._1+:101-}
A shorter one:
¿100 1+range@0$(::3%"Fizz"\{_""!}\5%"Buzz"\{_""!}+:~{_!})#"\n"join@.\
See also
- Project Euler Problem 1, a problem similar to FizzBuzz
External resources
References
- ↑ I. Ghory, Using FizzBuzz to find developers who grok coding. 2007. https://imranontech.com/2007/01/24/using-fizzbuzz-to-find-developers-who-grok-coding/
- ↑ R. Braithwaite, Don't overthink FizzBuzz. http://weblog.raganwald.com/2007/01/dont-overthink-fizzbuzz.html
- ↑ J. Atwood, Why can't programmers... program? https://blog.codinghorror.com/why-cant-programmers-program/