Talk:＿

The proof seems incorrect, because of $, which allows reading of other characters. --Yayimhere2(school) (talk) 10:48, 5 January 2026 (UTC)

The idea of the proof is that the program can't grow quickly enough to outrun the instruction pointer (only match it at best), so it doesn't really matter what $ does if it doesn't help the program grow any faster. –PkmnQ (talk) 11:37, 5 January 2026 (UTC)

I Guess not, but that part still needs to be edited out of the proof --Yayimhere2(school) (talk) 11:38, 5 January 2026 (UTC)