User talk:Yayimhere/INFINITIES

If i'm not getting it wrong, it gets up to φ(1,1,1)

Cleverxia (talk)

Maybe, I dont really know, but sure. I only really know up to ε₀(and identified up to there). feel free to show me how. --Yayimhere2(school) (talk) 14:25, 4 April 2026 (UTC)

[3 x]=w^x
[4 ωx]=ω^^(ωx)~εx
[5 ωx]=w^^^(ωx)~ζx
[ω ω]~Γ0
[ω [ω ω]]=[ω Γ0]~ω{ω}Γ0~Γ1
<ω ω ω>=Γω
v(x)~φ(1,0,x)
x{-1}x~φ(1,1,0)
Limit~φ(1,1,1)

also, please don't use ordinal hyperoperation next time. Cleverxia (talk) 14:31, 4 April 2026 (UTC)

Why not? can I not do what I want to at the end of the day? --Yayimhere2(school) (talk) 14:32, 4 April 2026 (UTC)

ordinal hyperoperation is not too well defined --(this comment by Cleverxia at 14:41, 4 April 2026 UTC; please sign your comments with ~~~~)