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The proof seems incorrect, because of $, which allows reading of other characters. --Yayimhere2(school) (talk) 10:48, 5 January 2026 (UTC)
- The idea of the proof is that the program can't grow quickly enough to outrun the instruction pointer (only match it at best), so it doesn't really matter what
$does if it doesn't help the program grow any faster. –PkmnQ (talk) 11:37, 5 January 2026 (UTC)- I Guess not, but that part still needs to be edited out of the proof --Yayimhere2(school) (talk) 11:38, 5 January 2026 (UTC)