Talk:Il

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just other's opinions about esolang

Just increment and decrement... Iloveunicorns (talk) 10:55, 16 September 2025 (UTC)

WHO CAN WRITE SHORTEST INTERPRETER???

i=p=0;c=input()+" "
for x in c:exec({"I":"i+=1","l":"i-=1"}.get(x,"i")+";p+=1")if c[p+1:]!=""else print(i)

tried my best

User:Gaham (Discord:mrglebsun)

By abstracting the summation and using a dispatch dictionary which builds intermediate integers instead of code snippets, we can write a single-stage function:

lambda s:sum({"I":1,"l":-1}[c] for c in s)

Some of the existing interpreters don't care about invalid inputs. If invalid inputs or comments are a serious concern then we can use the .get() method of dictionaries:

lambda s:sum({"I":1,"l":-1}.get(c,0) for c in s)

We can apply directly to input() for a one-liner that can be invoked with python3 -c:

print(sum({"I":1,"l":-1}.get(c,0) for c in input()))

This doesn't appear to get shorter when using map() or the functools or operator modules, although I invite golfers to keep trying. The secret insight is that Il admits a monoid! Corbin (talk) 15:53, 17 September 2025 (UTC)

clever

User:Gaham (Discord:mrglebsun)

For the one that doesn't care about invalid inputs, the dictionary can be replaced with a slightly smaller expression to get lambda s:sum(ord(c)%2*2-1 for c in s). I might try seeing how other esolangs do later, I think some of them could make a ridiculously short interpreter. –PkmnQ (talk) 01:43, 18 September 2025 (UTC)