# Talk:Bueue

This is very interesting. The only thing that seems to be known is that an infinite number may generate an infinite amount of subprograms. If we chose n in 2^{n} large enough we could generate a chosen amount of subprograms. For this reason it may also be of interest to study the behaviour of programs of the form 2^{n}.
A number 2^{n} will be divided by 2 n times, generating a sequence of n numbers.
Because Bueue works with the decimal radix (if you had chosen to convert the number to binary, one could I think more easily write programs in this language, but there would be less features), it may be a better idea to use powers of 10 though.
Since 10^{n} = (2 * 5)^{n} = 2^{n} * 5^{n}, a program of the form 10^{n} will first generate n sub-programs, and then will generate as many sub-programs as generated by 5^{n}. For the latter we can again not predict much, although the former may allow us to predict the first part of the actions of a given number.
--AnotherTest (talk) 13:17, 17 February 2013 (UTC)

The example programs are flawed, really: this would be true if it printed the direct bits as output, but it doesn't. In both cases the queue has a length less than 8 and so nothing is printed.

The smallest number that outputs a full byte is 15, which prints 11100010. 31 prints some characters and 36 prints 兩 . The first number that yields something sensical is 37 which gives 't'. I'm gonna keep looking... Imaginer1 (talk) 16:43, 20 September 2014 (UTC)

- Hm? 11000011694 enqueues 8 bits, 6 flips the first bit and 9 prints those 8 bits as a byte. -- Feuermonster (talk) 11:34, 24 September 2014 (UTC)