Talk:Hollang

Could you clarify "holographically embed them into variables"? How does averaging two bitstrings work, some operation between an and and an or?--Zerk (talk) 19:21, 17 April 2014 (EDT)


 * Averaging them works by literally averaging the zeros and ones at each position, and then for each bit rounding it to either 0 or 1 stochastically (so if the average for that bit is closer to 0 it will be rounded to zero more often). This makes it so that the average resembles all the components. The link on my homepage has the paper that I got all this information from.
 * --Doesthiswork (talk) 22:11, 17 April 2014 (EDT)


 * So essentially any even number of values in brackets is treated as having an extra random term?
 * --Zerk (talk) 00:00, 18 April 2014 (EDT)


 * No, it averages all the terms in the brackets before dithering the average to 0 and 1
 * --Doesthiswork (talk) 00:07, 18 April 2014 (EDT)
 * Ooh, the paper mentions permutations as a non self-inverse transformation, any plans to add those? It'd definitely solve your add:3:3 = add:1:1 = 2a -> 2 issue.
 * --Zerk (talk) 01:06, 19 April 2014 (EDT)